100x^2-1100x+1800=0

Solution for 100x^2-1100x+1800=0 equation:

100x^2-1100x+1800=0

a = 100; b = -1100; c = +1800;
Δ = b2-4ac
Δ = -11002-4·100·1800
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1100)-700}{2*100}=\frac{400}{200}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1100)+700}{2*100}=\frac{1800}{200}
=9
$